"2的63次方"编程

1 #include <stdio.h>
2 int main()
3 {
4 unsigned long long aa = 1;
5 int i = 0;
6
7 for (i = 1; i < 64; i++)
8 {
9 aa *= 2;
10 }
11 printf("%llu\n", aa);
12
13 return 0;
14 }

说得不够清楚

我用java写个
import java.util.*;
public class test{
public static void main(String[] args){

int aa = 1;

for (i = 1; i < 64; i++)
{
aa *= 2;
}
System.out.println(aa);
}

}